Series Solution around singular point

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SUMMARY

The discussion centers on solving the ordinary differential equation (ODE) given by x(2 - x)y'' - (x - 1)y' + 2y = 0 using series solutions around the regular point x = 1. The proposed solution takes the form y(x) = ∑(c_n)(x - 1)ⁿ, where n ranges from 0 to infinity. A suggestion to change variables from x to u = x - 1 is made to simplify the algebra involved in substituting the series into the ODE. The feasibility of obtaining a polynomial solution is questioned, indicating potential issues with the original differential equation formulation.

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  • Experience with algebraic manipulation of series solutions
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  • Study the method of Frobenius for solving ODEs near regular singular points
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Students and educators in mathematics, particularly those focusing on differential equations and series solutions, as well as researchers seeking to deepen their understanding of ODEs and their applications.

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Homework Statement



x(2 - x)y'' - (x - 1)y' + 2y = 0
Find the general solution in terms of a polynomial and a series in powers of x - 1.

Homework Equations


The Attempt at a Solution


Does the question basically ask for a series solution of the ODE at the regular point x = 1?
Then y(x) = \sum^{∞}_{n = 0}c_{n}(x - 1)^{n}
If I sub that into the ODE then I get a rather complicated algebraic mess for x(2 - x)y''. Is this the right way to solve this?
 
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Try changing variables from x to u=x-1. That'll simplify the algebra a bit.

I don't see how you're going to get a polynomial solution. Did you type the DE as given?
 
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