Set Theory Identities: A = B if A, B, and C satisfy key set relations

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SUMMARY

In set theory, the identity A = B can be concluded if sets A, B, and C satisfy the conditions A ∪ C = B ∪ C and A ∩ C = B ∩ C. Counterexamples demonstrate that these conditions do not guarantee A = B, as shown with sets A = {a, b, c}, B = {c, d, e}, and C = {a, b, c, d, e}. To prove A = B, one must establish A ⊆ B and B ⊆ A using set identities and properties of union and intersection. Utilizing a set that measures the difference between A and B can simplify the proof process.

PREREQUISITES
  • Understanding of set operations: union (∪) and intersection (∩)
  • Familiarity with subset notation (⊆)
  • Knowledge of set identities and properties
  • Basic concepts of lattice algebra
NEXT STEPS
  • Research set identities, including properties of union and intersection
  • Study lattice algebra and its relation to set theory
  • Explore the concept of set difference and how to measure differences between sets
  • Learn about complementation in set theory and its identities
USEFUL FOR

Students studying set theory, mathematicians exploring set identities, and educators teaching foundational concepts in mathematics.

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Homework Statement



Can you conclude that A = B if A, B, and C are sets such that

A [tex]\cup[/tex] C = B [tex]\cup[/tex] C and A [tex]\cap[/tex] C = B [tex]\cap[/tex] C


Homework Equations



The above is part c of a problem. The problems a and b are as follows

A) A [tex]\cup[/tex] C = B [tex]\cup[/tex] C

My answer: I gave a counter example such that A = {a, b, c}, B = {c, d, e}
and C = {a, b, c, d, e}, thus A [tex]\cup[/tex] C = C = B [tex]\cup[/tex] C
but A [tex]\neq[/tex] B

B) A [tex]\cap[/tex] C = B [tex]\cap[/tex] C

My answer: I gave the counter example where A = {a, b, c}, B = {c, d, e}, C = {c}
So, A [tex]\cap[/tex] C = C = B [tex]\cap[/tex] C but A [tex]\neq[/tex] B

The Attempt at a Solution



Ok for this part c I could not think of a counter example. I believe they want me to use set identities. I'm honestly not sure where to begin but Ill tell you what I have in mind so far.

If A [tex]\cup[/tex] C = B [tex]\cup[/tex] C, this implies that (A [tex]\cup[/tex] C) [tex]\subseteq[/tex] (B [tex]\cup[/tex] C), and (B [tex]\cup[/tex] C) [tex]\subseteq[/tex]
(A [tex]\cup[/tex] C)

So, (A [tex]\cup[/tex] C) [tex]\subseteq[/tex] (B [tex]\cup[/tex] C)

Same goes for (A [tex]\cap[/tex] C) [tex]\subseteq[/tex] ( B [tex]\cap[/tex] C),

In order to prove A = B I need to prove A [tex]\subseteq[/tex] B and B [tex]\subseteq[/tex] A.

So I have these premises and a conclusion, but I am honestly not sure how to set this up. I'm pretty sure I need to use set identities.. If anyone has any advice to get me moving here I'd greatly appreciate it, thanks!
 
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I don't think it's too hard to prove this by looking at elements in combination with algebraic identities, rather than a purely algebraic proof, if you are inclined to do so.


Rather than trying to prove that A=B, you may find it easier constructing a set that measures how different A and B are, and then proving something about that.


What identities are you considering using? Rewriting equality in terms of subsets is a place to start, but you don't seem to have invoked any properties of union and intersection yet.

I imagine you're probably using a list like the one here, along with the ones in the next section relating meet and join to ordering.

(In your case, the set-theoretic symbols [itex]\cap, \cup, \subseteq[/itex] correspond to the lattice algebra symbols [itex]\wedge, \vee, \leq[/itex])

FYI, that list of identities is not enough. You need these as well.

You may find identities relating to complementation useful too.
 

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