Setting Up Triple Integral for Region Bounded by x=y^2, z=0, x+z=1

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To set up the triple integral for the region bounded by x=y^2, z=0, and x+z=1, the limits of integration for z are from 0 to 1-x. The limits for y are from -sqrt(x) to +sqrt(x). The x integral should range from 0 to 1. A visual representation of the region can aid in understanding the boundaries. The discussion emphasizes the importance of correctly identifying the limits for each variable in the integral setup.
stratusfactio
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Homework Statement


Set up the triple integral for the region bounded by:

x=y^2, z=0, x+z=1

Homework Equations


The Attempt at a Solution


y= ±sqrt(x); z=0 & z=x+1
I'm just lost on how to find the x integral. I know the dz integral goes from z=0 to z=x+1, and I know the dy integral goes from y=-sqrt{x} to +sqrt{x}. I also know if we set 0=x+1, we get x=1, but how do I find the remaining limit of integration?
 
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Hi stratusfactio! :smile:

Your maximum z is a little off, it should be 1-x.

As for x, what's wrong with 0 to 1?
(I suggest you try to make a drawing.)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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