Shannon's Formula c = b log2 (1 + s)

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SUMMARY

Shannon's formula, expressed as c = b log2(1 + s), is correctly applied in the example discussed, where the signal-to-noise ratio (s) is 127 and bandwidth (b) is 3000. By adding 1 to the signal-to-noise ratio, it becomes 128, and the logarithm base 2 of 128 is 7. Multiplying this value by the bandwidth yields a channel capacity (c) of 21000 Bps, confirming the calculation's accuracy when presented clearly.

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  • Understanding of Shannon's Theorem
  • Knowledge of logarithmic functions, specifically log base 2
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  • Basic grasp of bandwidth in data transmission
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Radiatedtheory18
im trying to understand shannon's formula for some time now. i have tryed to theorise if this is correct the way i have worked out an example using the formula below.

c = b x log2 (1 + s)

for example

signal to noise ratio 127
b = 3000 b = bandwidth
as shannon's formula states to add one to the signal to noise ratio to make it 128

Log 2 = 27= 128

then we multiply the log2 by the bandwidth to get

21000 Bps

C=BXL

in formula the answer

21000 = 3000 x log2

is that correct?
 
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You get the right answer, but your presentation is confusing. You should state clearly that the log of 128 to the base 2 is 7, and then show the multiplication of that 7 by 3000 to give the answer 21000.

The way you have it now gives a first impression of being wrong.
 
128 = log to the base 2 is 27

7 x 3000 = 21000bps
 

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