Sharp Turning & Changing Direction: Physics Explained

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Sharp turning and changing direction involve the same principles as gentle turning, governed by Newton's Laws of Motion. The curvature, denoted as κ, increases with sharper curves, affecting the dynamics of motion. The position of an object over time can be described using vectors, where the tangent vector (T) and normal vector (N) play crucial roles in understanding acceleration and velocity. The relationship between curvature and velocity is essential, as sharper turns require greater centripetal acceleration. This discussion highlights the importance of curvature in the physics of motion, particularly in sharp turns.
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What is the physics of sharp turning; sharp curves and changing direction about those curves?
 
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Unless you have a specific unstated issue in mind then the answer is that it's the same physics as for gentle turning, curves and changing direction, i.e. Newton's Laws of Motion.
 
modeman said:
What is the physics of sharp turning; sharp curves and changing direction about those curves?

Curvature:
\kappa = \left| {\frac{{d\vec T}}{{ds}}} \right| = \frac{{\left| {\vec T\,'\left( t \right)} \right|}}{{\left| {\vec r\,'\left( t \right)} \right|}} = \frac{{\left| {\vec r\,'\left( t \right) \times \vec r\, {''}\left( t \right)} \right|}}{{\left| {\vec r\,'\left( t \right)} \right|^3 }}

Sharper curves have larger values of \kappa.

Curvature has its physical applications; for example, let \vec r ( t ) represent the position of an object at time t. You know that
\left\{ \begin{gathered}<br /> \vec T = \frac{{\vec r\,&#039;}}<br /> {{\left| {\vec r\,&#039;} \right|}} = \frac{{\vec v}}<br /> {{\left| {\vec v} \right|}} \Rightarrow \vec v = \left| {\vec v} \right|\vec T \hfill \\<br /> \kappa = \frac{{\left| {\vec T\,&#039;} \right|}}<br /> {{\left| {\vec r\,&#039;} \right|}} = \frac{{\left| {\vec T\,&#039;} \right|}}<br /> {{\left| {\vec v} \right|}} \Rightarrow \left| {\vec T\,&#039;} \right| = \kappa \left| {\vec v} \right| \hfill \\<br /> \vec N = \frac{{T\,&#039;}}<br /> {{\left| {T\,&#039;} \right|}} \Rightarrow T\,&#039; = \vec N\left| {T\,&#039;} \right| = \kappa \left| {\vec v} \right|\vec N \hfill \\ <br /> \end{gathered} \right\}

And so, making the necessary substitution,
\begin{gathered}<br /> \vec a = \vec v \, &#039; = \left| {\vec v} \right| &#039; \vec T + \left| {\vec v} \right|\vec T&#039; \Rightarrow \hfill \\<br /> \vec a = \left| {\vec v} \right| &#039;\vec T + \kappa \left| {\vec v} \right|^2 \vec N \hfill \\ \end{gathered}

Hope this helps :smile:
 
This is studied under 'TNB Physics' which constitutes the T=Unit Tangent vector N= Principle vector and B Vector . The curvature given by 'k' is defined by rate of change of unit normal vector per unit length.

BJ
 
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