Solving a Displacement-Time Graph with Sharp Turnings

  • Context: Undergrad 
  • Thread starter Thread starter Listin
  • Start date Start date
  • Tags Tags
    Graph Sharp
Click For Summary

Discussion Overview

The discussion revolves around converting a displacement-time graph with sharp turnings into a velocity-time graph. Participants explore the implications of sharp points on differentiability and continuity, considering both theoretical and practical aspects of graph interpretation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants note that sharp points in the displacement graph indicate non-differentiability, raising questions about how to represent the velocity graph in such cases.
  • One participant suggests that in real-world scenarios, sharp points are unrealistic due to the infinite rate of change of velocity they imply, which would require infinite force.
  • Another participant proposes that sharp points could result from infrequent sampling or insufficient graph scale, leading to apparent discontinuities.
  • It is mentioned that if the graph is treated as a mathematical ideal, a circle could be used in the velocity graph to indicate a discontinuity.
  • One participant provides an example illustrating how the velocity graph would behave with sharp corners in the displacement graph, showing constant velocities on segments and discontinuity at the sharp points.
  • Another participant highlights that high school physics often uses piecewise linear graphs, where average velocities can be calculated for segments, but instantaneous values at connection points pose challenges.

Areas of Agreement / Disagreement

Participants express differing views on how to handle sharp turnings in displacement graphs, with no consensus on a definitive approach to converting them into velocity graphs. The discussion remains unresolved regarding the best method to represent these transitions.

Contextual Notes

Participants acknowledge limitations related to the assumptions of differentiability and the nature of real-world data versus mathematical ideals. The discussion reflects varying interpretations of how to approach the conversion of graphs with sharp points.

Listin
Messages
1
Reaction score
0
I got a problem described by a displacement time graph. It has sharp turnings at 2 points ( and sucessives) and the question is to convert the graph to velocity time graph. Since sharp pionts are not differentiable how it can be drawn ?
 
Physics news on Phys.org
Listin said:
I got a problem described by a displacement time graph. It has sharp turnings at 2 points ( and sucessives) and the question is to convert the graph to velocity time graph. Since sharp pionts are not differentiable how it can be drawn ?

This is a little tricky to answer because in a class room setting it depends on your professor's perspective.

In the real world there cannot be perfectly sharp points as that implies an infinite rate of change of velocity and therefor infinite force being applied.

Is the graph produced from real data? If so, the sharp point is either a matter of infrequent sampling missing the points that would clearly define the change of velocity there, or it could be that the scale of the graph is not sufficiently fine to show the rapid change.

Could the professor be trying trying teach you this by giving you an apparently impossible graph?

If you want to test the graph as not necessarily bound by natural law (i.e., as a mathematical ideal), could use the math notation of inserting a circle in the velocity time graph to in indicate a discontinuity.
 
If there are sharp corners in the displacement graph, the velocity graph will not be continuous there. For example, if the displacement graph is straight line from (0, 0) to (5, 10) and then changes to the straight line from (5, 10) to (10, 10). The velocity will be the constant (10- 0)/(5- 0)= 2 from 0 to 5, then the constant (10-10)/(10-5)= 0 from 5 to 10. The velocity graph will be the horizontal line from (0, 2) to (5, 2), then the horizontal line from (5, 0) to (10, 0).
 
It is quite common in high school physics to show graphs of the motion (position-time and velocity-time) made from straight line segments connected at various angles.
Usually the questions related to these graphs regard the values at various points on the segments or average values for a segment, in which case there is no problem.
If they ask for instantaneous values at these connection points, then there is a problem.

If the question is just to convert to v-t graph then they may expect you calculate the average velocity on each segment and build another graph made from straight lines.
 

Similar threads

  • · Replies 49 ·
2
Replies
49
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K