Shear failure in threaded fasteners

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SUMMARY

The discussion centers on deriving a formula to prove that a bolt will not fail due to shear stress when the length of thread engagement equals the bolt diameter. The equation provided, A_s,e = pi*n*L_e*K_nmax*[1/2n + 1/sqrt3*(E_s,min-K_nmax)], calculates the shear area of an external threaded fastener but is deemed insufficient for proving shear failure resistance. The consensus is that the minimum recommended length of engagement is between 0.75 to 1 times the bolt major diameter for steel and 1 to 1.5 times for softer materials like brass and aluminum.

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  • Understanding of shear stress in mechanical engineering
  • Familiarity with threaded fasteners and their specifications
  • Knowledge of material properties affecting shear strength
  • Basic grasp of fastener design principles
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  • Research the shear strength of various materials used in fasteners
  • Study the mechanics of threaded fasteners in engineering texts like "Bickford" on fastener strength
  • Learn about the effects of thread engagement length on shear failure
  • Explore advanced calculations for shear area in external threaded fasteners
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Mechanical engineers, fastener designers, and students studying material strength and threaded fastener applications will benefit from this discussion.

krithika
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Hi
How can i derive an equation to prove that a bolt won't fail due to shear stress if the length of thread engagement of the bolt with nut is equal to the diameter of the bolt.

I got a formula, but i don't know whether it is useful in this case.

A_s,e = pi*n*L_e*K_nmax*[1/2n + 1/sqrt3*(E_s,min-K_nmax)]
where
n=threads/inch
L_e=Length of engagement
K_nmax=maximum inner diameter of nut
E_s,min=minimum pitch diameter of bolt

thanks
 
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Are you talking shear stresses in the threads or in the bolt shank? You are listing the shear area for failure of the threads.
 
The shear stress in thread.

Thanks for your response :)
 
The equation you state is the calculation of the shear area of an external threaded fastener. It is in a slightly different form than what I am used to, but it is fine the way you have it. The easy thing about your question is that you are putting the constraint that the engagement is equal to 1D. That is the way most shear area tables for fasteners is made. The tables list shear area for threads when Le = 1D. Tables like this are available in texts like Bickford and others on fastener strength.
 
Thanks for your reply. I think the formula what is stated (FOR Shear area) is of no use. What I'm looking for is a derivation or a formula which can say that the bolt won't fail due to shear stress, if Length of engagement between = the dia of the bolt. But unfortunately i couldn't find it anywhere :(.

Thanks for your support
 
krithika said:
What I'm looking for is a derivation or a formula which can say that the bolt won't fail due to shear stress, if Length of engagement between = the dia of the bolt. But unfortunately i couldn't find it anywhere :(.
Think about it first.

What does it mean if the bolt does not fail by shear in the threads?
 
Need to take into account the material fastner is made out of, nylon, mild steel, galvanised, zinc coated, high tensile, stainless steel.
Being able to shear will depend on how maluble the material is
 
To make things simple.
the length of engagement of bolt = diameter of the bolt.

But i don't know how to prove that it won't fail. I couldn't find a concrete material for this.
I am a kid in this field. So i need your advice.
 
  • #10
The minimum recommended length of engagement is 0.75 to 1 times the bolt major diameter for threading into steel and other materials of comparable hardness; and 1 to 1.5 times the bolt major diameter for threading into brass, cast iron, and aluminum. These lengths of engagement specified are for full threads engaged, not overall bolt length.
 
  • #11
could someone please help me in this regard.
 

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