Sheer stress due to a hole puncher

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Homework Help Overview

The problem involves calculating the shear stress exerted by a hole punch on multiple sheets of paper. The hole punch has a specified diameter and applies a known force, with the thickness of the paper also provided. The original poster seeks assistance in understanding how to arrive at the expected answer for shear stress.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the appropriate area to use for calculating shear stress, with some suggesting the need to consider the thickness of the paper and the circumference of the hole punch. There are questions about the calculations leading to an order of magnitude discrepancy in the results.

Discussion Status

Participants are actively engaging with the problem, offering insights and questioning the assumptions made about the area relevant to shear stress. There is a recognition of the need to clarify the relationship between the applied force, the area, and the thickness of the paper, but no consensus has been reached on the correct approach.

Contextual Notes

There is a hint provided in the original post regarding the area to consider for shear stress calculations. Participants are also noting the importance of understanding how the shear area relates to the applied force and the geometry of the hole punch.

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A hole punch has a diameter of 8mm and presses onto 10 sheets of paper with force of 6.7kN. IF each sheet of paper is of thickness .2mm, find the shear stress. [HINT: Be careful in decing what area to use. Remember that a shear force acts parallel to the surface whose area is relavant.]

shear stress= F/A

can anybody help me with this question from Physics by Giambattista.
The answer is supposed to be 1.3x10^8 Pa but i can't go about figuring out how they reach the answer.

tia
 
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maxxed said:
A hole punch has a diameter of 8mm and presses onto 10 sheets of paper with force of 6.7kN. IF each sheet of paper is of thickness .2mm, find the shear stress. [HINT: Be careful in decing what area to use. Remember that a shear force acts parallel to the surface whose area is relavant.]

shear stress= F/A

can anybody help me with this question from Physics by Giambattista.
The answer is supposed to be 1.3x10^8 Pa but i can't go about figuring out how they reach the answer.

tia
you were given the hint on which area to use. The paper must punch through by forces acting parallel to the direction of the applied force. Consider the circumference of the punch and the depth of the punctured paper.
 
hmm

I get an answer an order of magnitude off by just taking 6.7E3 / (10*(pi*(0.004m)^2)) = 1.33E7.

That's just using 10*[area one side of circle formed by holepunch]. Doesn't take into account the paper thickness, which may be why it's wrong. Maybe your book has a relevant example in the section?
 
sippyCUP said:
I get an answer an order of magnitude off by just taking 6.7E3 / (10*(pi*(0.004m)^2)) = 1.33E7.

That's just using 10*[area one side of circle formed by holepunch]. Doesn't take into account the paper thickness, which may be why it's wrong. Maybe your book has a relevant example in the section?
You're using the wrong values. The shear area which is parallel to the applied force has nothing to do with the surface area of the punch. And the shear stress depends on the shear area which must depend on the thickness of the paper sheets and the circumference of the 8mm circle.
 
Diagram attached.
 

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thanks for the input and the diagram everybody.
 

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