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Sheer stress due to a hole puncher

  1. Nov 19, 2007 #1
    A hole punch has a diameter of 8mm and presses onto 10 sheets of paper with force of 6.7kN. IF each sheet of paper is of thickness .2mm, find the shear stress. [HINT: Be careful in decing what area to use. Remember that a shear force acts parallel to the surface whose area is relavant.]

    shear stress= F/A

    can anybody help me with this question from Physics by Giambattista.
    The answer is supposed to be 1.3x10^8 Pa but i cant go about figuring out how they reach the answer.

  2. jcsd
  3. Nov 19, 2007 #2


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    you were given the hint on which area to use. The paper must punch through by forces acting parallel to the direction of the applied force. Consider the circumference of the punch and the depth of the punctured paper.
  4. Nov 19, 2007 #3

    I get an answer an order of magnitude off by just taking 6.7E3 / (10*(pi*(0.004m)^2)) = 1.33E7.

    That's just using 10*[area one side of circle formed by holepunch]. Doesn't take into account the paper thickness, which may be why it's wrong. Maybe your book has a relevant example in the section?
  5. Nov 19, 2007 #4


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    You're using the wrong values. The shear area which is parallel to the applied force has nothing to do with the surface area of the punch. And the shear stress depends on the shear area which must depend on the thickness of the paper sheets and the circumference of the 8mm circle.
  6. Nov 20, 2007 #5
    Diagram attached.

    Attached Files:

  7. Nov 20, 2007 #6
    thanks for the input and the diagram everybody.
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