1. The problem statement, all variables and given/known data Two lengths of steel plate 100mm wide and 15mm thick are riveted together by a single 18mm diameter rivet. If the joint carries a tensile load of 8kN calculate: a) The shear stress in the rivet b) The tensile stress in the perforated plate 2. Relevant equations stress = force / cross sectional area 3. The attempt at a solution a) stress = force / cross sectional area = 8x10^3 / pi/4(0.018)^2 = 31.43MPa This is the answer given in the textbook so I am satisfied it is correct. b) This is where I am stuck. The given answer is 6.51MPa. I thought maybe if I use 100mmX15mm (1500mm) as the area for the plate and subtract the area of the 18mm diameter rivet (pi/4(0.018)^2) I could divide the 8kN force (although this is the tensile load of the joint) by this area and get the stress for the plate. However if I do the above: 8x10^3 / [(1.5x10^-3)-pi/4(0.018)^2] = 6.42MPa Where am I going wrong?