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**1. Homework Statement**

Two lengths of steel plate 100mm wide and 15mm thick are riveted together by a single 18mm diameter rivet. If the joint carries a tensile load of 8kN calculate:

a) The shear stress in the rivet

b) The tensile stress in the perforated plate

**2. Homework Equations**

stress = force / cross sectional area

**3. The Attempt at a Solution**

a) stress = force / cross sectional area

= 8x10^3 / pi/4(0.018)^2

= 31.43MPa

This is the answer given in the textbook so I am satisfied it is correct.

b) This is where I am stuck.

The given answer is 6.51MPa.

I thought maybe if I use 100mmX15mm (1500mm) as the area for the plate and subtract the area of the 18mm diameter rivet (pi/4(0.018)^2) I could divide the 8kN force (although this is the tensile load of the joint) by this area and get the stress for the plate.

However if I do the above:

8x10^3 / [(1.5x10^-3)-pi/4(0.018)^2]

= 6.42MPa

Where am I going wrong?