Find the shortest distance between A(2,1,-2) and the line having parametic equations:
d = |AB| sin( arccos( (AB.BC)/|AB||BC| ) )
B and C are points on the line found by putting random values for t.
For t=0 -> B(3,-4,1)
For t=1 -> C(1,-1,3)
The Attempt at a Solution
Plugging the values in the above equation, we get:
d = 6 sin (arccos 11/6sqrt(17) )
Using the calculator gives the correct answer, but there is another way which I can't figure out, in which you get the answer irrespective of sin and arccos.
What is it?
Thanks in advance :)