meter stick pivoted at point a from its center and swings as a physical pendulum. At which values of a gives you the shortest period of oscillation.....1m, .2m, .3m, .4m. .5m
T = 2pi*Sqrt(I/mgh)
The Attempt at a Solution
the shortest a should give you the shortest period. The longer the distance = longer period but the answer is .3...why?