How Does a Circular Hoop's Oscillation Period Change When Displaced by a Breeze?

[Safinaz]

Homework Statement

the period of a physical pendulum is $2\pi \sqrt{I/mgh},$ where I is the moment of
inertia about the pivot point and d is the distance from the pivot to the
centre of mass. A circular hoop hangs from nail on a barn wall. The
mass of the hoop is 3 kilogram and its radius is 20 centimetre . If it
is displaced slightly by a passing breeze, what is the period of the
resulting oscillation.

Homework Equations

What is the solution ?

The Attempt at a Solution

I thank about as a motion of torsion pendulum, whose $T= 2 \pi \sqrt{I/c}$, with $I = MR^2$, and c is the twisting coupling.

 

[gneill]

Look up "Physical Pendulum". The hyperphysics website gives a good summary.