Should I memorize all these trigonometric integrals?

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SUMMARY

The discussion centers on the necessity of memorizing trigonometric integrals and identities for calculus. Participants emphasize that while basic identities like `sin(x) = cos(x)` and `cos(x) = -sin(x)` are essential, memorizing specific integral formulas such as ∫ sec^2(x) dx = tan(x) + C is crucial for success in calculus. The consensus is that understanding the derivation of these identities can aid in retention, and practicing problems will make these formulas second nature over time. Texts like Larson's Calculus and Thomas' Calculus provide foundational proofs and insights into these derivatives.

PREREQUISITES
  • Understanding of basic trigonometric functions and their derivatives
  • Familiarity with integral calculus concepts
  • Knowledge of calculus textbooks, specifically Larson's Calculus and Thomas' Calculus
  • Ability to perform differentiation and integration of trigonometric functions
NEXT STEPS
  • Study the proofs of trigonometric derivatives in Larson's Calculus
  • Practice integration problems involving secant and cosecant functions
  • Explore the relationship between trigonometric identities and their derivatives
  • Review Thomas' Calculus for additional insights on trigonometric properties
USEFUL FOR

Students of calculus, mathematics educators, and anyone seeking to strengthen their understanding of trigonometric integrals and derivatives.

Byeonggon Lee
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I only memorized these trigonometric differential identities :
`sin(x) = cos(x)
`cos(x) = -sin(x)

because I can convert tan(x) to sin(x) / cos(x) and
sec(x) to 1 / cos(x) .. etcAnd there is no need to memorize some integral identities such as :
∫ sin(x) dx = -cos(x) + C
∫ cos(x) dx = sin(x) + C

because I memorized
`sin(x) = cos(x)
`cos(x) = -sin(x)But these identities seem inevitable to memorize:
∫ sec^2(x) dx = tan(x) + C
∫ cosec^2(x) dx = -cot(x) + C
∫ sec(x)tan(x) dx = sec(x) + C
∫ cosec(x)cot(x) dx = -cosec(x) + C

For example
∫ sec^2(x) dx = tan(x) + C

First I tried to convert sec^2(x) to 1 / cos^2(x)
∫ sec^2(x) dx = ∫ (1 / cos^2(x)) dx

And that's where I'm stuck.
It looks impossible to proceed anymore without memorizing a trigonometric differential identity
`tan(x) = sec^2(x)
 
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Byeonggon Lee said:
It looks impossible to proceed anymore without memorizing a trigonometric differential identity
`tan(x) = sec^2(x)
How about remembering how to derive a fraction? \frac{d}{dx}(\frac{\sin x}{\cos x})=\frac{\sin 'x\cdot \cos x - \cos 'x\cdot \sin x}{\cos ^{2}x}=\frac{\cos^{2}x+\sin^{2}x}{\cos ^{2}x}=\frac{1}{\cos ^{2}x}
 
After the course, all of those should be second nature.
 
don't worry about memorizing them. As you perform integration overtime they will come second nature as stated above. Just make sure to do many practice problems each lesson/chapter
 
just memorize the derivatives of sin, sec, and tangent. then the others are minus the cofunctions of those. i.e. if d/dx sec = sec.tan, then d/dx csc = -csc.cot. etc...
 
My habit is always to go back to first principles. In the case of the derivatives of trigonometric functions, I simply memorized the derivatives of the sine and cosine. I'm not sure what Calculus textbooks you all have used, but the one I went through (Larson, 8th edition) did not give a proof that the derivative of sine is cosine, but did use this fact to establish the other derivatives and anti-derivatives. Other than this counter-example, Larson was great at showing proofs.

Do I have to wait till Advanced Calculus to find the proof that the derivative of the sine is the cosine?
 
David Carroll said:
Do I have to wait till Advanced Calculus to find the proof that the derivative of the sine is the cosine?
You shouldn't have to, no.
 
What am I talking bout, Arnold? I looked back to Larson's Calculus and there was such a proof. I was wrong.
 
David Carroll said:
What am I talking bout, Arnold? I looked back to Larson's Calculus and there was such a proof. I was wrong.
Yes, it would very surprising for a calculus text to not show a proof of at least one trig function, using the definition of the derivative. Once you have the derivative of either sine or cosine, then you can get the derivatives of the other trig functions by the use of other techniques. IOW, if it has been proven that d/dx(sin(x)) = cos(x), then you can get d/dx(cos(x)) by noting that ##cos(x) = sin(\pi/2 -x)##, and differentiating the latter using the chain rule.
 
  • #10
David Carroll said:
What am I talking bout, Arnold? I looked back to Larson's Calculus and there was such a proof. I was wrong.

Thomas calculus with analytic geometry 3rd ed, has a very nice proof. Can be found for 10 dollars max, and it is supperior to Larson. It also shows the trigonometric properties and how they can be derived from 2 graphs.
 
  • #11
Please do not link to copyrighted books illegally posted on the internet.
 
  • #12
That wasn't illegally posted on the internet.
 
  • #13
Thats for sure that you have to memorize all the trigonometric integrals formula or you can simply learn the base formula and with some multiplying or substracting it goes to another formula, but if you are in a test memorizing those formulas are a good key for you.
 

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