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## Homework Statement

In Cartesian coordinates the magnitude of the velocity vector squared is

|v|^2=V*V= Vx^2 +Vy^2 =(dx/dt)^2+(dy/dt)^2

Show that in polar coordinated

|v|^2= Vr^2 +V@ ^2

## Homework Equations

## The Attempt at a Solution

Not really sure what the question is asking me to do, but i am guessing to convert (dx/dt)^2+(dy/dt)^2 into polar? or do i need to do it for all of it?

Well I got dy/dt=(dr/d@) sin@+rcos@ and dx/dt=(dr/d@) cos@-rsin@

Is this right? Were do i go after this?

Thanks