Show square inscribed in circle has maximum area

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The discussion focuses on proving that a square inscribed in a circle has the largest area among all four-sided polygons. Participants suggest expressing the area of a quadrilateral as a function of its side lengths to find the maximum area. A specific case of a rectangle is noted as easier to analyze, leading to the conclusion that the area can be maximized using calculus. The area formula for a quadrilateral inscribed in a circle is provided, indicating that the maximum area occurs when the angles between sides are 90 degrees, confirming the square's superiority. The conversation emphasizes the need for trigonometric principles to support the proof.
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Homework Statement


Show that the square, when inscribed in a circle, has the largest area of all the 4-sided polygons. Try to show that all sides of a quadrilateral of maximal area have to be of
equal length.

The Attempt at a Solution


How do you start?
I don't get how showing the sides are equal will help prove that the square has maximal area.
Any hints?
 
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Try to express surface of the inscribed 4-sided polygon as a function of the length of its sides. General case will be more difficult, but for a specific case of rectangle it should be relatively easy to express lengths as a function of one variable.

Once you have that, find maximum.
 
Borek said:
Try to express surface of the inscribed 4-sided polygon as a function of the length of its sides. General case will be more difficult, but for a specific case of rectangle it should be relatively easy to express lengths as a function of one variable.

Once you have that, find maximum.

I don't quite understand.
Say I have a square, let the side length = a.

area = a^2.
Then maximize by taking derivative?
 
Real easy to prove with coordinate geometry, but you need to know the parametric equation of a circle and the area of a quadrilateral.

Any point on a circle (with origin as centre and radius r) is (r cosx, r sinx)
and area of a quadrilateral with vertices (x1, y1), (x2, y2), (x3, y3), (x4, y4),
is #8 here http://www.mathisfunforum.com/viewtopic.php?id=3301

take four points, put them in the formula, the result becomes obvious
 
that gives me the area, but it doesn't prove that it is the maximum area for a 4 sided shape.
 
it does! the result for area of a general quadrilateral in a circle comes to be (assuming radius r and angles A, B, C, D
r2/2[sin(A-B) + sin(B-C) + sin(C-D) + sin(D-A)]
the maximum value of which (2r2) is attained only when each of the angular differences is 90 degrees which results in a square

did u try solving it? you need basic trignometric formulae
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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