Show that a group has exactly one idempotent element

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Homework Help Overview

The problem involves proving that a group has exactly one idempotent element, specifically the identity element. The discussion centers around the definitions and properties of groups, particularly focusing on the concept of idempotent elements.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the definition of idempotent elements and the implications of the identity element being idempotent. Questions arise regarding the uniqueness of idempotent elements and the application of the cancellation law in proving this uniqueness.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on the logical steps needed to demonstrate that the identity element is the only idempotent element. Some guidance has been offered regarding the use of the cancellation law and the properties of group elements.

Contextual Notes

Participants are navigating the definitions and properties of groups, including the existence of inverses and the implications of the identity element's properties. There is an emphasis on rigor in the logical steps taken to prove the uniqueness of the idempotent element.

Mr Davis 97
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Homework Statement


Prove that a group has exactly one idempotent element.

Homework Equations

The Attempt at a Solution


So we need to show that the identity element is the unique idempotent element in a group.

First, we know that by definition of a group there is at least one element, e, such that ##e * e = e##.

Second, we need to show that there is at most one idempotent element. We do this by showing that if ##x*x=x## and ##y*y=y## then ##x=y##... This is as far as I get. Am I on the right track?
 
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Mr Davis 97 said:

Homework Statement


Prove that a group has exactly one idempotent element.

Homework Equations

The Attempt at a Solution


So we need to show that the identity element is the unique idempotent element in a group.

First, we know that by definition of a group there is at least one element, e, such that ##e * e = e##.

Second, we need to show that there is at most one idempotent element. We do this by showing that if ##x*x=x## and ##y*y=y## then ##x=y##... This is as far as I get. Am I on the right track?
What does it mean for ##x\cdot x = x^2=x\,##? Any idea to get rid of one ##x\,##?
 
fresh_42 said:
What does it mean for ##x\cdot x = x^2=x\,##? Any idea to get rid of one ##x\,##?
I can use the cancellation law. But how does that logically show that e is the unique element in the group that is idempotent?
 
Mr Davis 97 said:
I can use the cancellation law. But how does that logically show that e is the unique element in the group that is idempotent?
If ##x## is any idempotent element, i.e. ##x^2=x## then you can multiply (as in school on both sides) the whole equation with ##x^{-1}##, which is probably what you meant by cancellation. You can do this, because all elements of a group have an inverse. Then - if you want to be very rigorous and pedantic - you can apply associativity and the existence and definition of ##e##. Write it down and see what it says.
 
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Mr Davis 97 said:
First, we know that by definition of a group there is at least one element, e, such that ##e * e = e##.
You know more than that about e. You know x*e=x. Use that. The fact that e*e = e should tell you that you need to prove that x=e.
 

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