Show that f is continious at 0 (easy but confused)

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SUMMARY

The function f defined by the inequality |f(x)| ≤ |x| is continuous at 0. The proof involves showing that for every ε > 0, there exists an α > 0 such that for all x in the domain, if |x| < α, then |f(x) - f(0)| < ε. The solution manual simplifies this by stating that choosing α = ε suffices to demonstrate continuity. This approach clarifies the relationship between ε and α in the context of limits.

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Homework Statement



let f be a function t: lf(x)l≤lxl
show that f is continious at 0

The Attempt at a Solution


it's easy to see that f(0)=0
now \forallE>0 \existsα>0 \forallx\inD: lxl<α => lf(x)-f(0)l<E now in the solution manual they just put it like this : since lxl<α implies lf(x)-(f(0)=0)l<E then f i s continious at a , what I'm not getting is that they didn't give alpha a value they just want from x<alpha to the result ? I've been studying limits since 2012 so this is a weird issue to me , please help
 
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Just take α=E.
 
thanks i forgot a bit about the first definition that's why i had trouble ,i've got it now
 

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