Show that the initial speed is vi = sqrt 2gL(l-cosθ).

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Homework Statement


An object of mass m is suspended from the top of a cart by a string of length L. The cart and object are initially moving to the right at a constant speed vi. The cart comes to rest after colliding and sticking to a bumper, and the suspended object swings through an angle θ.
(a) Show that the initial speed is vi = sqrt 2gL(l-cosθ).
(b) If L = 2.0 m and θ = 40.0°, find the initial speed of the cart.


Homework Equations


KE = PE
1/2mv2 = mgh
L1= L-(Lcosθ)


The Attempt at a Solution


1/2mv2 = mgh
v2 = 2mgh/m
v = sqrt 2gh
stuck!
 
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Did you draw a diagram? Look at the situation. How can you express the height the object moves through in terms of the length of the string?