Show That x(n) is a Cauchy Sequence for 0<r<1

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    Cauchy Sequence
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SUMMARY

For the sequence x(n) defined under the condition 0 < r < 1 and the inequality |x(n+1) - x(n)| < r^n for all n, it is established that x(n) is a Cauchy sequence. The definition of a Cauchy sequence requires that for every ε > 0, there exists an N such that for all m, n > N, |x(m) - x(n)| < ε. By applying the given inequality, one can demonstrate that the terms of the sequence become arbitrarily close as n increases, fulfilling the Cauchy criterion.

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If 0<r<1 and |x(n+1) - x(n)| < r ^n for all n. Show that x(n) is Cauchy sequence.
help please.
 
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You may have at least written & used the definition of a Cauchy sequence...
 

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