Show the range of f is isomorphic to a quotient of z

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SUMMARY

The discussion focuses on demonstrating that the range of the function f: Z → G defined by f(n) = a^n is isomorphic to the quotient group Z/nZ using the first isomorphism theorem. It is established that the range of f is {a^n ∈ G | n ∈ Z}, and the kernel of f is {m ∈ Z | am = e}. To apply the first isomorphism theorem effectively, it is crucial to confirm that f is a homomorphism and to verify that (Z, +) is indeed a group.

PREREQUISITES
  • Understanding of group theory and group homomorphisms
  • Familiarity with the first isomorphism theorem
  • Knowledge of quotient groups, specifically Z/nZ
  • Basic concepts of kernel in the context of group homomorphisms
NEXT STEPS
  • Study the first isomorphism theorem in detail
  • Learn about the properties of quotient groups, particularly Z/nZ
  • Explore examples of homomorphisms and their kernels in group theory
  • Review the structure of the integers under addition to reinforce group concepts
USEFUL FOR

Students of abstract algebra, particularly those studying group theory, and educators seeking to clarify the application of the first isomorphism theorem in practical examples.

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Homework Statement


Let G be any group and a in G, define f: Z → G by f(n) = a^n

Apply any isomorphism theorem to show that range of f is isomorphic to a quotient group of Z

Homework Equations

The Attempt at a Solution


The range of f is a^n , then quotient group of Z is Z/nZ
Apply the first isomorphism theorem , we have a^n isomorphic with Z/nZ
 
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if you can show that f is a homomorphism & find its kernel then you'll have your isomorphism by the first isomorphism theorem. the range of f is actually {an ∈ G | n ∈ Z}, not just an. the kernel of f is {m ∈ Z | am = e}, not nZ (but you're not far off). you might need to show that (Z, +) is a group in order to make sure that f is actually a group homomorphism, unless you've already established that in your class.
 
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