Show this simple trigonometric identity add up to 0

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SUMMARY

The discussion centers on the trigonometric identity involving the expression \(\cos\left(\frac{(-1)\pi x}{L}\right) - \cos\left(\frac{3\pi x}{L}\right)\). The user attempts to simplify the expression by substituting values for \(x\) and \(L\), specifically \(x = 1\) and \(L = 3\). The calculations reveal that the identity does not equal zero for all \(x\), as demonstrated by the evaluation of \(\cos(-\pi/3) - \cos(\pi)\), which yields a positive result. The discussion highlights the properties of cosine, particularly \(\cos(-x) = \cos(x)\) and the cubic cosine identity.

PREREQUISITES
  • Understanding of trigonometric functions, specifically cosine.
  • Familiarity with trigonometric identities, including \(\cos(-x) = \cos(x)\).
  • Knowledge of the cubic cosine identity: \(\cos(3x) = 4\cos^3(x) - 3\cos(x)\).
  • Basic algebraic manipulation skills to simplify trigonometric expressions.
NEXT STEPS
  • Study the derivation and applications of the cubic cosine identity.
  • Explore advanced trigonometric identities and their proofs.
  • Learn about the graphical representation of cosine functions and their transformations.
  • Investigate the implications of cosine properties in solving trigonometric equations.
USEFUL FOR

Students studying trigonometry, educators teaching trigonometric identities, and anyone interested in understanding the properties and applications of cosine functions in mathematical contexts.

td21
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Homework Statement


[tex]\cos (\frac{(-1)\pi x}{L})-\cos (\frac{3\pi x}{L})[/tex]


Homework Equations





The Attempt at a Solution


the first cosine is the same as positive but is the second cosine simply equal to
[tex]\cos (\frac{\pi x}{L})[/tex]?


thanks!
 
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When x = 1, L = 3, we have:

cos(-pi/3) - cos(pi)
= 1 + cos(-pi/3) > 0
 
[tex]\cos(-x)=\cos(x)[/tex]
and
[tex]\cos(3x)=4\cos^3(x)-3\cos(x)[/tex]

So obviously this isn't going to be equal to 0 for all x.
 

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