Showing continuous function has min or max using Cauchy limit def.

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SUMMARY

The discussion centers on proving that a continuous function \( f: \mathbb{R} \to \mathbb{R} \) achieves a maximum or minimum value given that \( \lim_{x \to \infty} f(x) = \lim_{x \to -\infty} f(x) = l \), where \( l \) can be either a real number or \( \pm \infty \). The proof utilizes the Weierstrass theorem and specific limit definitions. Participants clarify the choice of \( N \) as \( \max\{R_1, -R_2\} \) to ensure that for \( |x| > N \), the function \( f(x) \) exceeds a certain bound \( M \). The discussion also addresses the correct formulation of limits approaching \( -\infty \).

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CGandC
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Problem: Let ## f: \Bbb R \to \Bbb R ## be continuous. It is known that ## \lim_{x \to \infty } f(x) = \lim_{x \to -\infty } f(x) = l \in R \cup \{ \pm \infty \} ##. Prove that ## f ## gets maximum or minimum on ## \Bbb R ##.

Proof: First we'll regard the case ## l = \infty ## ( the case where ## l = -\infty ## is similar ). Denote ## | f(0) | = M ##. By the given there exists ## N>0 ## large enough s.t. for all ## |x| > N ## , ## f(x) > M \geq f(0) ##. [ The proof continues by using weierstrass theorem, finishes for the infinite case, and then it proves for the case where ## l ## is finite ]

My question: I was wondering about how they got to the phrase in red. I know they used the definitions for ## \lim_{x \to \infty } f(x) = \infty ## , ## \lim_{x \to -\infty } f(x) = \infty ## which are:
## \lim_{x \to \infty } f(x) = \infty \iff ## ## \forall M>0 .\exists R_1>0. \forall x \in (R_1,\infty). f(x) > M ##
## \lim_{x \to -\infty } f(x) = \infty \iff ## ## \forall M<0 .\exists R_2<0. \forall x \in (-\infty,R_2). f(x) > M##

What instantiation they used and how did they choose ## N ##? ( did they chose ## N := max \{ R_1 , |R_2| \} ## after instantiating a variable in the universal quantifiers? ) how from these two definitions I get to the phrase in red?

Thanks in advance for the help and advice!
 
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Yes, your choice should work. if you chose ##N = \max{\{R_1, -R_2\}}## and you assume ##|x| > N##, knowing that, by definition ##N > R_1##, ##N > -R_2## what can you say about ##x## and ##R_{1,2}##?
 
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I can say that ## x > N > R_1 ## or ## x< -N < R_2 ##.
If ## x > N > R_1 ## then ## f(x) > M ##
If ## x< -N < R_2 ## then ## f(x) > -|M| ##.

How do I get ## f(x) > M ## for both cases ( for ## x > N > R_1 ## or ## x< -N < R_2 ## )?
 
For ##x<-N \leq R_2## you still have f(x)>M. It's directly coming from the definition of the limit. The limit is positive infinity.
 
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CGandC said:
## \lim_{x \to -\infty } f(x) = \infty \iff ## ## \forall M<0 .\exists R_2<0. \forall x \in (-\infty,R_2). f(x) > M##

What instantiation they used and how did they choose ## N ##? ( did they chose ## N := max \{ R_1 , |R_2| \} ## after instantiating a variable in the universal quantifiers? ) how from these two definitions I get to the phrase in red?

Thanks in advance for the help and advice!
The above line is wrong. You have to say for all M>0 and the rest remains as it is. Don't forget, even though our independent variable x goes to minus infinity, the limit remains positive infinity so it has to be for all M>0.
 
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Thank you. With this correction things sit perfectly well!

I have one more question - Is the following definition for ## \lim\limits_{x \to +\infty} f(x) = -\infty ## correct?:
## \lim\limits_{x \to +\infty} f(x) = -\infty \iff \forall M<0 .\exists R>0. \forall x \in (R,\infty). f(x) < M ##
 
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Yes looks fine to me, now the limit is minus infinity so it should be for all ##M<0## (or alternatively M>0 but we require ##f(x)<-M##.
 
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Ok thanks for the help! that'd be all.
 
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