Showing that a bessel function satisfies a particular equation

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Homework Help Overview

The discussion revolves around demonstrating that the equation y'' + ((1+2n)/x)y' + y = 0 is satisfied by the function x-nJn(x), where Jn(x) represents a Bessel function. Participants are exploring the differentiation of this function and its implications in the context of the given differential equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to differentiate the function and substitute it into the differential equation, but expresses uncertainty about the correctness of their derivatives. Some participants question the differentiation process, suggesting the use of the product rule, while others note the potential reliance on properties of Bessel functions.

Discussion Status

The discussion is ongoing, with participants providing pointers and suggestions for differentiation techniques. There is a focus on ensuring the correct application of mathematical rules without assuming properties of Bessel functions, indicating a productive exploration of the problem.

Contextual Notes

There is mention of potential confusion regarding the differentiation of the Bessel function and the application of the product rule. The original poster also expresses a need for guidance, indicating that they may be struggling with the assumptions or properties related to Bessel functions.

1Kris
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Hi, I'm stuck on this question from a calculus book;
Show that y'' + ((1+2n)/x)y' + y = 0 is satisfied by x-nJn(x)

Is it correct that when I differentiate that, I get these:
y= x-nJn(x)
y'=-x-nJn+1(x)
y''=nx-n-1Jn+1(x) -
x-n(dJn+1(x)/dx)?

The Attempt at a Solution


Equation in question becomes:
x-n(2(n/x)Jn+1 - Jn - ((1+2n)/x)Jn+1 + Jn)

= x-n(-x-1Jn+1)
but this isn't 0.

Sorry if I'm repeating myself here but I could just do with some kind of a pointer.
Thanks, Kris
 
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Shouldn't y' = -nx-n-1Jn(x) + x-nJ'n(x) ? You have to use the product rule.
 
I think the OP is using some property of the Bessel functions to get that expression for y'. I could very well be wrong though; I don't remember much about the Bessel functions.
 
Just crank it out, without resorting to any special properties and relations of the Bessel functions. Use the product rule to get y' and y'', plug them into the differential equation, and simplify.
 

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