Showing that these two integrals are equal

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The discussion revolves around proving the equality of two integrals, with emphasis on understanding the factor of 2 that appears in the process. Participants suggest evaluating both integrals directly to see their equivalence and clarify the role of the factor. A key point made is that if a function is even, such as f(x) = e^x + e^{-x}, the integral from -a to a can be simplified to twice the integral from 0 to a. The symmetry of the functions e^x and e^{-x} around zero is highlighted as a fundamental concept. Overall, the conversation encourages a deeper exploration of integral properties and function symmetry.
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These two are equal to each other, but I can't figure out how they can be that.

1604049271124.png


I know that 2 can be taken out if its in the function, but where does the 2 come from here?
 
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Why not evaluate the integrals to check they are the same?

If you do that you might see for yourself where the ##2## comes from.
 
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so do i solve for the integral on the left side and end up with the integral on the right?? Or do i solve them just as they are written above? (I have solved the equation with values, but don't really know how to do this one. )
 
conv said:
so do i solve for the integral on the left side and end up with the integral on the right?? Or do i solve them just as they are written above?(I have solved the equation with values, but don't really know how to do this one. )
I suggest you evaluate both integrals. And check they are equal.

I assume you know how to integrate ##e^x## and ##e^{-x}##?
 
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i understood it. Thanks
 
conv said:
i understood it. Thanks

More generally, if ##f(x) = f(-x)## then ##\int_{-a}^a f(x) = 2\int_0^a f(x)##. On the other hand, if ##f(x) = -f(-x)## then ##\int_{-a}^a f(x) = 0##. Can you see why ##f(x) = e^x + e^{-x}## satisfies ##f(x) = f(-x)##?
 
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This should be almost self-evident and not difficult to argue from the symmetry around 0 between the two functions ##e^x## and ##e^{-x}##. If in doubt about that, plot them. Which would only be reminding yourself of what you should securely know already. Not clever but rather basic.

ETA OK this is equivalent to what etotheipi says.
 

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