MHB Showing that two elements of a linearly independent Set Spans the same set

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The problem involves proving that the sets {v1, v2} and {v2, v3} span the same subspace in a vector space V, given the condition v1 + v2 + v3 = 0. It is established that both v2 and v3 can be expressed in terms of v1 and v2, leading to the conclusion that span({v2, v3}) is a subset of span({v1, v2}). Conversely, since v1 can be expressed as -v2 - v3, it follows that span({v1, v2}) is also a subset of span({v2, v3}). Thus, both spans are equal, confirming that span({v1, v2}) = span({v2, v3}). The discussion effectively demonstrates the relationship between linear combinations and vector spans in linear algebra.
shen07
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Hi, i would like to have a hint for the following problem:

Let $$v_1, v_2 \&\ v_3 $$ in a vector space V over a field F such that$$ v_1+v_2+v_3=0$$, Show that $\{v_1,v_2\}$ spans the same subspace as $\{v_2,v_3\}$

Thanks in advance
 
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shen07 said:
Hi, i would like to have a hint for the following problem:

Let $$v_1, v_2 \&\ v_3 $$ in a vector space V over a field F such that$$ v_1+v_2+v_3=0$$, Show that $\{v_1,v_2\}$ spans the same subspace as $\{v_2,v_3\}$

Thanks in advance
Note that $v_2$ and $v_3$ are both contained in $\text{span}(\{v_1,v_2\})$ (why?). Thus $\text{span}(\{v_2,v_3\})\subseteq \text{span}(\{v_1,v_2\})$.

Similarly $\text{span}(\{v_1,v_2\})\subseteq \text{span}(\{v_2,v_3\})$.

Therefore $\text{span}(\{v_1,v_2\})=\text{span}(\{v_2,v_3\})$.
 
In general, if you have two sets of vectors $A$ and $B$ and every vector of $B$ is expressible through vectors of $A$, then $\mathop{\text{span}}(B)\subseteq \mathop{\text{span}}(A)$.
 
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