Showing two groups are *Not* isomorphic

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SUMMARY

The discussion centers on demonstrating that the group \(\mathbb{Z}_{4}\oplus \mathbb{Z}_{4}\) is not isomorphic to \(\mathbb{Z}_{4}\oplus \mathbb{Z}_{2}\oplus \mathbb{Z}_{2}\). Key to this proof is analyzing the elements of order 4 within the groups. The participant correctly identifies that the element (2,0) in \(\mathbb{Z}_{4}\oplus \mathbb{Z}_{4}\) has order 2, derived from the least common multiple of the orders of its components, confirming the validity of their approach.

PREREQUISITES
  • Understanding of group theory concepts, specifically direct sums of groups.
  • Knowledge of the structure and properties of cyclic groups, particularly \(\mathbb{Z}_{n}\).
  • Ability to compute the order of elements in groups.
  • Familiarity with least common multiples (LCM) in the context of group orders.
NEXT STEPS
  • Research the properties of direct sums in group theory.
  • Study the classification of finite abelian groups and their isomorphism types.
  • Learn how to compute the order of elements in direct sum groups.
  • Explore examples of groups with different structures to solidify understanding of isomorphism.
USEFUL FOR

This discussion is beneficial for students of abstract algebra, particularly those studying group theory, as well as educators looking to clarify concepts related to group isomorphism and element orders.

DeldotB
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Homework Statement


Good day,

I need to show:

\mathbb{Z}_{4}\oplus \mathbb{Z}_{4}is not isomorphic to \mathbb{Z}_{4}\oplus \mathbb{Z}_{2}\oplus \mathbb{Z}_{2}

Homework Equations



None

The Attempt at a Solution



I was given the hint that to look at the elements of order 4 in a group. I know \mathbb{Z}_{4}\oplus \mathbb{Z}_{4} will have the elements: (0,0)(0,1)(0,2)(0,3)(1,0)(1,1)...(3,3).

Im a little confused on how to find the order of say (1,2) in \mathbb{Z}_{4}\oplus \mathbb{Z}_{4}.
I know how to find the order of say <3> in \mathbb{Z}_{4} (order=4/gcd(3,4)=4) but how can I do it with the direct sum elements?

Thanks in advance!
 
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Can anyone tell me this is correct:

In Z4 direct sum Z4, say we look at the element (2,0)
Since <2> has order 2 in Z4 and <0> has order one in Z4, it follows that (2,0) has order 2 because the lcm(2,1) is 2?
 
DeldotB said:
Can anyone tell me this is correct:

In Z4 direct sum Z4, say we look at the element (2,0)
Since <2> has order 2 in Z4 and <0> has order one in Z4, it follows that (2,0) has order 2 because the lcm(2,1) is 2?

Correct. The conclusion is clearly correct since (2,0)+(2,0)=(0,0). Try some others until you can see why that rule works.
 
Last edited:

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