Isomorphism of dihedral with a semi-direct product

  • #1

Homework Statement


Let m ≥ 3. Show that $$D_m \cong \mathbb{Z}_m \rtimes_{\varphi} \mathbb{Z}_2 $$
where $$\varphi_{(1+2\mathbb{Z})}(1+m\mathbb{Z}) = (m-1+m\mathbb{Z})$$

Homework Equations


I have seen most basic concepts of groups except group actions. Si ideally I should not use them for this problem.

The Attempt at a Solution


So I've been thinking about this problem for a couple of days and I just can't seem to arrive to the proof I am looking for.

And so we have that <s> is cyclical of order 2 and <r> is cyclical of order m. Therefore, $$\langle s \rangle \cong \mathbb{Z}_2$$
and $$\langle r \rangle \cong \mathbb{Z}_m$$
I feel I have to use the fact that <r> is normal in Dm and that <r>∩<s> = {e}. I unsure where to go from there

Thanks for the help
 

Answers and Replies

  • #2
I suggest to write it in terms of ##r## and ##s## first, and then see how it translates to ##\mathbb{Z}_m##, resp. ##\mathbb{Z}_2##. And I will write the representatives, aka elements of ##\mathbb{Z}_m## as ##[k] = k+m\mathbb{Z}## which is more convenient and easier to read.

In general a semidirect product ##G = N \rtimes_\varphi H## goes by ##(n_1\, , \,h_1)\cdot (n_2\, , \,h_2) \stackrel{(*)}{=} (n_1 \cdot \varphi(h_1)(n_2)\, , \,h_1\cdot h_2)##, see e.g. https://en.wikipedia.org/wiki/Semidirect_product. We have ##\varphi\, : \,H \longrightarrow \operatorname{Aut}(N)##.

Here we have products ## P =(r^k\; , \;s^\varepsilon)\cdot (r^n\; , \;s^\eta) = r^k\cdot s^\varepsilon \cdot r^n \cdot s^\eta## with ##\varepsilon \in \{\,0,1\,\}##.
Now write ##P## in the form ##P=r^l \cdot s^\mu=(r^l,s^\mu)## and compare that with ##(*)## to see how ##\varphi(s^\varepsilon)(r^n)## has to be defined.
If you're done, you can write this as ##\varphi([\varepsilon])([n])##.

You have only defined ##\varphi([1])([1])##. What are ##\varphi([0])## and ##\varphi([1])([n])## if ##n>1## or short: What is ##\varphi([\varepsilon])## with ##\varepsilon \in \{\,0,1\,\} = \{\,[0],[1]\,\}\,?##
 

Suggested for: Isomorphism of dihedral with a semi-direct product

Replies
2
Views
470
Replies
2
Views
642
Replies
5
Views
663
Replies
6
Views
385
Replies
2
Views
183
Replies
2
Views
881
Replies
16
Views
888
Back
Top