Showing union of open sets is an open set?

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SUMMARY

The union of the open sets U_n, defined as U_n = {all p = (x, y) with |p - (0, n)| < n} for n = 1, 2, 3, ..., is proven to be the open upper half-plane. Each U_n represents a circle centered at (0, n) with radius n, encompassing all points whose distance from this center is less than n. By selecting a point p = (x, y) in the upper half-plane where y > 0, it is established that there exists an n sufficiently large such that p lies within the circle defined by U_n. This demonstrates that the union of all U_n covers the entire open upper half-plane, excluding the horizontal axis.

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Homework Statement



Let U_n = {all p = (x, y) with |p - (0, n)| < n}. Show that the union of all the open sets U_n, for n = 1, 2, 3, ..., is the open upper half plane.

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The Attempt at a Solution



U_n describes points p whose distance from a set point on the vertical axis is smaller than the height of that point that is on the vertical axis. When you move the vertical axis point up and down, and combine all the sets of points created, you'll get the upper half plane not including the horizontal axis. I can picture it, but how do I begin to show it?
 
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Pick a point in the upper half plane p=(x,y) with y>0. Can't you figure out a way to find an n large enough the p is in the circle centered at (0,n) with radius n? This really isn't conceptually hard. n can be as large as you like. Figure out the intersection of the circle with the vertical line through the point. Make it less than y.
 

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