I was reading through an article on, "Shunt Reactors for Voltage Control" and I am slightly confused. (See link below for article)(adsbygoogle = window.adsbygoogle || []).push({});

http://www.onegrid.com.au/wp-content/uploads/2012/03/BR-EN-TH16-02_2006-Shunt_reactors_for_voltage_control.pdf

The article reads, "When the network load and particularly the high voltage network drops, the voltages on all the busbars increase due to the capacitive current in the transmission line."

It then goes on to say, "The voltage sensitivity to changes at one busbar due to small changes in real and reactive power at another busbar can be determined from the stability analysis expression."

[tex]dV_{i} = \frac{\partial V_{ij}}{\partial P} \dot dP_{j} + \frac{\partial V_{ij}}{\partial Q} \dot dQ_{j}[/tex]

"A simplified expression that is quite accurate in most cases is"

[tex]\Delta V_{i} = \frac{\Delta Q_{i}}{S_{SC}}[/tex]

What do they mean by capacitive currents, and how does that increase the voltage on the busbar?

How does adjusting the reactive power change the voltage levels?

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# Shunt Reactors for Voltage Control

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