Signals & Systems - what's the output?

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SUMMARY

The discussion centers on the output of a discrete-time system defined by the input signal x[n] = r[n] - 2r[n - 1] + r[n - 2] and the impulse response h[n] = δ[n - 2]. The proposed output y[n] = u[n - 3] is questioned, with one participant suggesting that the convolution of x[n] and h[n] results in y[n] = 0. The consensus indicates that the correct output requires further analysis of the convolution process.

PREREQUISITES
  • Understanding of discrete-time signals and systems
  • Familiarity with convolution operations in signal processing
  • Knowledge of unit step functions and impulse responses
  • Ability to analyze and sketch discrete-time signals
NEXT STEPS
  • Study the convolution theorem in discrete-time systems
  • Learn about the properties of impulse responses and their effects on system outputs
  • Explore the relationship between input signals and their corresponding outputs using MATLAB or Python
  • Investigate the role of unit step functions in signal processing
USEFUL FOR

Students and professionals in electrical engineering, particularly those focusing on signal processing and systems analysis, will benefit from this discussion.

Angello90
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Homework Statement


Input and system response is as follow:

[tex]x[n] = r[n] - 2r[n - 1] + r[n - 2][/tex]
[tex]h[n] = \delta[n - 2][/tex]

The output is:
[tex]y[n] = u[n - 3][/tex]

Is that true?


Homework Equations





The Attempt at a Solution


I draw the h[n] and x[n] and they looked as follows:
attachment.php?attachmentid=30426&stc=1&d=1291631179.jpg


As for me when these two are multiplied, it will become [tex]y[n]=0[/tex].
Am I right?

Thanks
 

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Can anyone give me a tip maybe? Thanks!
 

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