Simple Algebra Question: Finding the Value of X in Equations

[bengaltiger14]

I know this is not an algebra forum but this problem arose for me in physics.

Determine a numerical value for x:

((9^3)/27) = ((SQRT(24^4))/(3^x))

I move the 27 to the top and the 3^x to the top and then solve for x this way.

3 - 1 = 2 - x, this makes x equal to 0 but it is not right. What is the correct way to do this?

Also, determine x for: 3^2x = 7(3^x)

I used logs: 2xlog3=7(xlog3) The xlog3 will cancel and I can't solve for x anymore. Any recommendations?

 

[alphysicist]

I know this is not an algebra forum but this problem arose for me in physics.

Determine a numerical value for x:

((9^3)/27) = ((SQRT(24^4))/(3^x))

I move the 27 to the top and the 3^x to the top and then solve for x this way.

I would isolate the 3^x to one side of the equation by itself. Do you see what to do then?

3 - 1 = 2 - x, this makes x equal to 0 but it is not right. What is the correct way to do this?

Also, determine x for: 3^2x = 7(3^x)

I used logs: 2xlog3=7(xlog3) The xlog3 will cancel and I can't solve for x anymore. Any recommendations?

Try combining the terms algebraically first so that you only have one x in the equation.

 

[unscientific]

Complete Solution Removed

 

[bengaltiger14]

I solved the first problem and got 3, which is the correct answer.. Thanks.

I am still having problems with the next one. Do you divide both sides by 3^x and solve for x

 

[alphysicist]

I solved the first problem and got 3, which is the correct answer.. Thanks.

I am still having problems with the next one. Do you divide both sides by 3^x and solve for x

Yes, that's what I would do.