1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple classical physics inquiry

  1. Apr 25, 2015 #1
    [Mentor's note -- this post does not use the homework template because it was moved here from a non-homework forum.]

    ----------------------------------------------

    ImageUploadedByPhysics Forums1429994664.445878.jpg

    Not sure how the extra velocity quantity appears after deriving both side of the velocity function to get acceleration. Please help.
     
    Last edited by a moderator: Apr 25, 2015
  2. jcsd
  3. Apr 25, 2015 #2

    jtbell

    User Avatar

    Staff: Mentor

    You're given v as a function of x, not as a function of t. Therefore you have to use the chain rule: $$a = \frac{dv}{dt} = \frac{dv}{dx} \frac{dx}{dt}$$
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Simple classical physics inquiry
  1. Classical physic (Replies: 2)

Loading...