1. The problem statement, all variables and given/known datathere are 3 girls and 3 boys that are to sit in a row. How many ways are there for them to sit in a row if the boys must sit together? 2. Relevant equations n!=n(n-1)(n-2).....(3)(2)(1) 3. The attempt at a solution there are 4 possible positions for the boys. o 1 o 1 o 1 o the o's represent the group of 3 boys and the 1's each represent a girl. Within a o, there are 3! ways to arrange boys. And since there are 4 o's, there are 4! ways of arranging the o's. Just looking at the o's, we have, by counting, (3!)(4!) ways of arranging the boys. And since there are 3 1's, there are 3! ways of arranging the girls. The solution by counting is that there are (3!)(4!)(3!) ways for the boys and girls to be arranged in a row. But the book has it at (3!)(4!). Did I do something wrong?