Simple Contour Integration Question

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SUMMARY

The integral \(\int_{-\infty}^{\infty} \frac{e^{i2\pi ft}}{1+if}df\) is evaluated using contour integration by setting \(z = i*f\) and applying the residue theorem. The integral features a pole at \(z = -1\) and is analyzed for two cases: \(t > 0\) and \(t < 0\). The discussion emphasizes the importance of contour orientation and the placement of semi-circular contours to ensure the integral along these paths vanishes as limits approach infinity. The choice of contours and their directions is crucial for accurate evaluation.

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Homework Statement



We want to find the value of the integral \int_{-\infty}^{\infty} \frac{e^{i2\pi ft}}{1+if}df using contour integration.

Homework Equations



This should be solved by setting z = i*f and using the residue theorem. The equation has a pole at z = -1.

The Attempt at a Solution



I already have the solution, but I have trouble understanding it, so I hope someone here can enlighten me.

We divide the contour integral into two cases: t>0 and t<0. The diagram is shown http://img79.imageshack.us/img79/5793/contoursqm5.jpg .

I know the key here is to draw the semi-circle so that the integral along the semi-circle disappears as we extend the limits to infinity, but I'm unclear on how our solution came up with the contours. Especially the second one, since I was under the impression that all contours had to be "counterclockwise" - or at least, if we were walking along the line, the area enclosed in our contour should be on our left. This doesn't appear to be the case for the second case.

Can anyone help? My main problem is understanding how to choose where the semi-circles should go, but any clarification on the direction of the contour integral in the second case would be appreciated as well.

Thanks!
 
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I don't see why you have to use two contours in this case. I find the simplest way to compute these integrals would be to take a semi-circular contour with it's diameter being the real axis and an indented contour around the singularity on the boundary.

However, to answer your question, if we have a contour C oriented clockwise then;

\int_{-C}f(t)dt = -\int_{C} f(t)dt
 

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