Simple cosine expression NOT so simple

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    Cosine Expression
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Homework Help Overview

The discussion revolves around the integration of the function f(x) = Sqrt(1 + kcos(x)), with a focus on finding the area under the curve between x=0 and x=pi. The subject area involves calculus and specifically the integration of trigonometric expressions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore various methods for manipulating the expression, including substitutions and logarithmic transformations. Questions arise about the nature of the function and its integrability.

Discussion Status

Some participants suggest that the integral may not have a solution in terms of elementary functions and hint at the involvement of elliptic functions. There is acknowledgment of a helpful resource for integration, which has provided some participants with insights into the problem.

Contextual Notes

There is a mention of the original poster's struggle with the problem and a sense of discovery regarding the complexity of the integral involved. The discussion reflects a mix of attempts to simplify the expression and the realization of its potential complexity.

Mark Wood
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I am rediscovering my long lost "A" level maths and have been having lots of fun working on puzzles. Unfortunately, I seem to have hit something of a wall in the following simple expression that is repelling every attack I launch:

f(x)=[tex]Sqrt[/tex](1+kcos(x))

I have tried substituting x=arccos(w) and w=arccos(w/k), expressing things as logs, mungeing the equations I get, and a number of slightly more desperate attacks, but whatever I do to get rid of one term or provide something that can be canceled out, a new problem pops up.

I feel that there is a simple answer to this, but the more I look at it the less I can see the way forward.

Any suggestions anyone?
 
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What exactly do you want to do with f(x)?
 
Ah! So absorbed by it, I've missed the most important bit!

I'm trying to integrate it to get the area under the curve between x=0 and x=pi
 
Sorry, i couldn't get ur expression. is it (1+kcos(x))^(1/2)
 
Yes it is - the root of (1+kcos(x))
 
I don't think it has a solution made up entirely of elementary functions. Elliptic functions may be involved.
 
I too struggled for it for 6-8 months. Its a kind of elliptic integral(which i didn't knew). u might be knowing. u can check it on an integrator at www.wolfram.com
 
Gosh - what a great tip. I didn't know the integrator existed. Thank you.

Having got the answer from Wolfram I'm kind of pleased that I hadn't missed an obvious solution.

Thank you all.
 

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