Simple Derivative: e^nx Answer C

  • Thread starter Thread starter Qube
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary
SUMMARY

The derivative of the function enx is calculated using the rule that states the derivative of e raised to any function is e raised to that function multiplied by the derivative of the function itself. Therefore, the correct derivative is (enx)(n). The discussion clarifies that answer choice C, which represents the first derivative, is not the correct answer for the second derivative, prompting further exploration of higher-order derivatives such as the second and third derivatives of enx.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with the exponential function ex.
  • Knowledge of the chain rule in differentiation.
  • Ability to compute higher-order derivatives.
NEXT STEPS
  • Study the chain rule in calculus for differentiating composite functions.
  • Learn how to compute higher-order derivatives of exponential functions.
  • Explore the applications of derivatives in real-world scenarios.
  • Practice problems involving derivatives of functions of the form enx.
USEFUL FOR

Students studying calculus, particularly those focusing on derivatives of exponential functions, and educators looking for clarification on common misconceptions regarding differentiation.

Qube
Gold Member
Messages
461
Reaction score
1

Homework Statement

http://k.minus.com/j4eToABCaFgrW.png

Homework Equations



The derivative of e^anything = e^anything * (du/dx).

The Attempt at a Solution



So, wouldn't the answer choice be C? The derivative of e^nx = (e^nx)(n).
 
Last edited by a moderator:
Physics news on Phys.org
Qube said:

Homework Statement

http://k.minus.com/j4eToABCaFgrW.png

Homework Equations



The derivative of e^anything = e^anything * (du/dx).

The Attempt at a Solution



So, wouldn't the answer choice be C? The derivative of e^nx = (e^nx)(n).
No, it's not answer (C). (C) is the first derivative !

Start by looking at [itex]\displaystyle \frac{d}{dx}e^{nx}\,,\ \ \frac{d^2}{dx^2}e^{nx}\,,\ \ \frac{d^3}{dx^3}e^{nx}\,, \ \ \text{etc.}[/itex]
 
Last edited by a moderator:
Ohhh ... I get it :)! Thanks :D.
 

Similar threads

Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
9
Views
3K