(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

What is the time rate of change of height after 5.0s?

2. Relevant equations

theta = 3t/(2t + 10)

adjacent length = 1000

Therefore: opposite length (height) h = 1000 tan (3t/(2t+10))

3. The attempt at a solution

I thought it would be simply finding the derivative of the second equation (dh/dt) and plugging in 5 for t.

dh/dt = 1000 * ( sec(3t/(2t+10)) )^2 * [ (2t+10)*3 - 3t(2)/ (2t + 10)^2 ]

dh/dt |t=5 = 1000/(cos.75)^2 * 3/40

= 75.01...

75 m/s

Is this not correct?

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# Homework Help: Simple differentiatian of tan question

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