1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple differentiatian of tan question

  1. Nov 30, 2008 #1
    1. The problem statement, all variables and given/known data
    What is the time rate of change of height after 5.0s?


    2. Relevant equations

    theta = 3t/(2t + 10)
    adjacent length = 1000

    Therefore: opposite length (height) h = 1000 tan (3t/(2t+10))


    3. The attempt at a solution

    I thought it would be simply finding the derivative of the second equation (dh/dt) and plugging in 5 for t.

    dh/dt = 1000 * ( sec(3t/(2t+10)) )^2 * [ (2t+10)*3 - 3t(2)/ (2t + 10)^2 ]
    dh/dt |t=5 = 1000/(cos.75)^2 * 3/40
    = 75.01...

    75 m/s

    Is this not correct?
     
  2. jcsd
  3. Nov 30, 2008 #2

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    Change your calculator from degrees to radians. Otherwise, it looks great.
     
  4. Nov 30, 2008 #3
    Thank you. :smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Simple differentiatian of tan question
  1. Simple Simple question (Replies: 1)

  2. Simple Question (Replies: 19)

  3. Simple Question. (Replies: 3)

  4. Simple question (Replies: 7)

  5. Simple question (Replies: 4)

Loading...