Simple electric flux through tetrahedron problem

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SUMMARY

The discussion centers on calculating electric flux through a tetrahedron with a base of 20 cm edges in a vertical electric field of 200 N/C. The electric flux through the base is determined using the formula flux = EA, resulting in -3.464 Nm²/C, indicating a negative value due to the direction of the electric field. The flux through each of the three triangular sides is calculated to be 1.2 Nm²/C, reflecting the convention that outward flux is positive.

PREREQUISITES
  • Understanding of electric flux and its calculation using the formula flux = EA.
  • Knowledge of geometric properties of tetrahedrons, specifically equilateral triangles.
  • Familiarity with the concept of electric fields and their directionality.
  • Basic grasp of sign conventions in physics, particularly regarding flux through closed surfaces.
NEXT STEPS
  • Study the derivation and applications of Gauss's Law in electrostatics.
  • Learn about the geometric properties of polyhedra and their implications in physics.
  • Explore the concept of electric field lines and their relation to electric flux.
  • Investigate the implications of sign conventions in electric flux calculations for various geometries.
USEFUL FOR

Students and professionals in physics, particularly those focusing on electromagnetism, as well as educators teaching electric field concepts and their applications in geometric shapes.

kirby2
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A tetrahedron has an equilateral triangle base with 20-cm-long edges and
three equilateral triangle sides. The base is parallel to the ground and a
vertical uniform electric field of strength 200 N/C passes upward through
the object.
(a) What is the electric flux through the base?
(b) What is the electric flux through each of the three sides?

ATTEMPT:

for part a i used flux=EA. for A i used BH/2 and got .0173. i multiplied that by 200 and got 3.46 m^2/C. can someone verify this is correct?

for part b i just divided that number by 3 because the total flux in the sides must equal that of the base so i got -1.1533m^2/C. i think the sign is negative because it must have the opposite sign of the base. is this right?
 
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kirby2 said:
A tetrahedron has an equilateral triangle base with 20-cm-long edges and
three equilateral triangle sides. The base is parallel to the ground and a
vertical uniform electric field of strength 200 N/C passes upward through
the object.
(a) What is the electric flux through the base?
(b) What is the electric flux through each of the three sides?

ATTEMPT:

for part a i used flux=EA. for A i used BH/2 and got .0173. i multiplied that by 200 and got 3.46 m^2/C. can someone verify this is correct?

for part b i just divided that number by 3 because the total flux in the sides must equal that of the base so i got -1.1533m^2/C. i think the sign is negative because it must have the opposite sign of the base. is this right?
I agree with the magnitudes.

What is the convention for the sign of flux?
 
the convention is positive sign?
 
kirby2 said:
the convention is positive sign?
For a closed surface, what direction is positive? Inward or Outward ?
 
for a closed surface outward is positive
 
kirby2 said:
for a closed surface outward is positive

Good !

Then the flux through the base is negative, correct?
 
yes. and the sides are positive. thank you
 
a) -3.464 Nm^2/C

b) 1.2 Nm^2/C
 

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