Simple Fluid Mechanics-differential manometer question. Please

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The discussion revolves around solving a differential manometer problem involving a manometer fluid with a specific gravity of 3.46 and water in pipes A and B. The pressure in pipe A is decreased by 1.3 psi, while the pressure in pipe B increases by 0.9 psi. The calculated specific weight of the gage fluid is 215.904 lb/ft³, leading to a differential height of 4.06 ft, although one participant calculated 4.5641 ft. The correct approach involves adjusting the pressures in the equations used for the calculations.

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Simple Fluid Mechanics-differential manometer question. Please :)

Can someone please help me on this differential manometer question??

Let me retype the question because my handwriting is sloppy. "The manometer fluid in the manometer has specific gravity of 3.46. Pipes A and B both have water. If pressure in A is decreased by 1.3psi and pressure in B increases by 0.9psi, determine the differential.
Gamma(water) = 62.4 lb/ft^3
SG*Gamma(water)=Gamma(gage fluid)=(3.46)*(62.4lb/ft^3)=215.904lb/ft^3

I scanned what I did. I tried a few other methods but they were borderline retarded and didnt make sense so I didnt bother attaching them.

Please help!

Oh the answer is 4.06ft. The best I can muster is 4.5641ft.
 

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Your first equation of the Pressube in B is correct with respect to pressure in A, if the heights are correct (i don't know because you used variables not defined anywhere). Also, this equation do not represente the increase you forgot to add 0.9 to Pb and subract 1.3 to Pa.
 
cool thanks bro :) :)
 

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