- #1

- 603

- 6

## Homework Statement

## Homework Equations

Hydrostatic equation

## The Attempt at a Solution

Call length from 2 to the Hg "h".

Yhg = specific weight of Hg, from book = 846lbf/ft^3

Yw= water = 62.4 lbf / ft^3

Then

P2 = P1 + Yw(5sin45 + h + .5) - Yhg(.5) - Yw(h)

Then P2 - P1 = simplify and plug in numbers = 171.2 lbf/ft^2 = 1.19 PSI.

I get lost on the second part though. How am I supposed to know what is due to friction and which part the manometer reads? I'm assuming it ignores the weight of the fluid because it's the same in both places so it cancels out?