The Attempt at a Solution
Call length from 2 to the Hg "h".
Yhg = specific weight of Hg, from book = 846lbf/ft^3
Yw= water = 62.4 lbf / ft^3
P2 = P1 + Yw(5sin45 + h + .5) - Yhg(.5) - Yw(h)
Then P2 - P1 = simplify and plug in numbers = 171.2 lbf/ft^2 = 1.19 PSI.
I get lost on the second part though. How am I supposed to know what is due to friction and which part the manometer reads? I'm assuming it ignores the weight of the fluid because it's the same in both places so it cancels out?