Simple force/energy/work problem

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Homework Help Overview

The discussion revolves around a physics problem involving the calculation of minimum work required to push a car up an incline. The subject area includes concepts of force, work, and gravitational effects on an object on a slope.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the work formula but is uncertain about how to find the necessary force without given acceleration or velocity. Some participants suggest considering the balance of forces acting on the car and question the role of acceleration in this context.

Discussion Status

Participants are exploring various interpretations of the problem, particularly regarding the forces involved in moving the car up the incline. Some guidance has been offered about balancing gravitational forces and the implications of constant velocity, but no consensus has been reached on a specific approach.

Contextual Notes

There is a lack of explicit information regarding acceleration and velocity, which is causing confusion in applying the relevant formulas. The discussion also touches on the assumption of ignoring friction in the problem setup.

xecure
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simple force & work problem

I'm not very good as physics and the question i was having problems with is this: what is the minimum work needed to push a 950kg car 310m up along a 9.0 degree incline? (ignore friction)


the formula i was using is this: Work = Force * distance * cos(theta)

distance and theta was already given so i used F=ma to try and find the force needed, but the acceleration for the object is not given, and neither is velocity (so i am not able to use: [PLAIN]https://www.physicsforums.com/latex_images/90/905663-3.png)


What formula should i use? how should i go about doing this?
 
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You do the minimum work when pushing the car with a force that just balances the downward force of gravity along the slope, and do not waste work for acceleration. Well, you need to accelerate the car at the beginning so as it starts to move, but then just keep this low speed.

ehild
 
ehild said:
You do the minimum work when pushing the car with a force that just balances the downward force of gravity along the slope, and do not waste work for acceleration. Well, you need to accelerate the car at the beginning so as it starts to move, but then just keep this low speed.

ehild

I'm stumped, if acceleration does not come into play how would i go about doing this problem?
 
How much force have you exert to prevent a car rolling down a slope? You need just a bit more to push it up. Your work is this force multiplied by the length of the slope.
 
ehild said:
How much force have you exert to prevent a car rolling down a slope? You need just a bit more to push it up. Your work is this force multiplied by the length of the slope.

but I am having trouble finding the force, how would i go about calculating the force?
 
If you hold a bag of 10 kg what is the force you exert on the bag?

If you were so strong that you could lift that car of 950 kg and hold it, how much would be your force?

ehild
 
it would be m*a, which is 950kg * 9.81 = 9319.5
 
xecure said:
it would be m*a, which is 950kg * 9.81 = 9319.5

Does that car accelerate if it is in rest?

9.81 m/s2 is the acceleration of a body when it falls. Is the car falling? Acceleration means change of velocity. If a body is in rest, the velocity is zero, the acceleration is zero. If the body moves with constant velocity, the acceleration is zero.

The gravity of Earth is a force that acts on every body. It causes downward acceleration g on the free bodies. If you exert force equal to gravity but opposite to it, these forces will cancel and the car stays in rest or moves with constant velocity.

Gravity does work on a falling body. If the body falls from height h, the work of gravity is Wg=mgh. When you lift a body with zero acceleration, your force is equal to gravity, F=mg. Lifting the car at height h needs W=mgh work from you.

The slope is 310 m long and the angle of the incline is 9°. What is the height then?
Of course, you do not lift the car just vertically up, but it is pushed uphill. If there is no friction, no loss of energy, the work is the same either the car is moved up on the slope or raised up vertically : W=mgh.

ehild
 

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