Simple Forces question I cannot seem to get

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The minimum force required to set a couch weighing 620N into motion, given a coefficient of static friction of 0.31, is 192N. The calculation involves determining the force of friction using the formula Ff = μFn, where Fg (the weight of the couch) is equal to 620N. The mass of the couch is calculated as 63.2 kg, but finding the mass is unnecessary for this specific problem. The applied force must equal the force of friction for the couch to begin moving.

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Homework Statement


A couch weighing 620N is to be pushed to a new location across the room. The coefficient of static friction between the couch and the floor is 0.31. What is the minimum force required to set the couch into motion.

Homework Equations


See below

The Attempt at a Solution


Given: Fg=620N
μs=0.31
Required: Force applied
Analysis: In order for the couch to begin moving, the applied force must be equal to the force of friction. Therefore finding the force of friction will indirectly find the minimum force applied.
Solution: Find the mass of the couch by using Fg=mg=620N
mg=620N
m=620N/9.81m/s^2
m=63.2...kg (keep all the decimals)

then find Ff using Ff=μFn; since there is no vertical acceleration, Fg=mg. The question gave mg (620N) so...
Ff=(0.31)(620N)
Ff=192N [backwards]
Fa=192N [forwards]

Therefore 192N of force are required.

Is this solution correct?
 
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Element1674 said:

Homework Statement


A couch weighing 620N is to be pushed to a new location across the room. The coefficient of static friction between the couch and the floor is 0.31. What is the minimum force required to set the couch into motion.

Homework Equations


See below


The Attempt at a Solution


Given: Fg=620N
μs=0.31
Required: Force applied
Analysis: In order for the couch to begin moving, the applied force must be equal to the force of friction. Therefore finding the force of friction will indirectly find the minimum force applied.
Solution: Find the mass of the couch by using Fg=mg=620N
mg=620N
m=620N/9.81m/s^2
m=63.2...kg (keep all the decimals)

then find Ff using Ff=μFn; since there is no vertical acceleration, Fg=mg. The question gave mg (620N) so...
Ff=(0.31)(620N)
Ff=192N [backwards]
Fa=192N [forwards]

Therefore 192N of force are required.

Is this solution correct?

Looks ok to me. But you didn't need to to find m.
 

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