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Simple function/variable problem

  1. Jan 25, 2009 #1
    The base of an isosceles triange has length b and the two sides of equal length each measure 30 cm. Find the area A of the triangle as a function of b.


    a squared + b squared = c squared
    Area= .5bh

    .5b squared + h squared = 30 squared
    h= (-.5b squared + 900) ^ 1/2

    Area= .5 x b x [(-.5b squared + 900)^ 1/2]

    Is this correct?
     
  2. jcsd
  3. Jan 26, 2009 #2

    Gib Z

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    Homework Helper

    Well it is sort of ambiguous what you mean by the -.5b squared, but if you meant

    [tex] A = \frac{b}{2} \cdot \sqrt{ 900 - \frac{b^2}{4} }[/tex]

    as you probably did, then yes, its correct ! =]
     
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