- #1
wallace13
- 31
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The base of an isosceles triange has length b and the two sides of equal length each measure 30 cm. Find the area A of the triangle as a function of b.
a squared + b squared = c squared
Area= .5bh
.5b squared + h squared = 30 squared
h= (-.5b squared + 900) ^ 1/2
Area= .5 x b x [(-.5b squared + 900)^ 1/2]
Is this correct?
a squared + b squared = c squared
Area= .5bh
.5b squared + h squared = 30 squared
h= (-.5b squared + 900) ^ 1/2
Area= .5 x b x [(-.5b squared + 900)^ 1/2]
Is this correct?