# Simple Harmonic Motion and time calculation

1. Jun 22, 2009

### weskerq8

1. The problem statement, all variables and given/known data

An object is undergoing simple harmonic motion with period 0.280 s and amplitude 5.95 cm . At t=0 the object is instantaneously at rest at x= 5.95 cm.

Calculate the time it takes the object to go from x= 5.95 to x= -1.44 .

2. Relevant equations

X=A.cos(wt) ------> the phase angle in this case is zero (we won't worry about it)
w=2pi/T

3. The attempt at a solution

I have used the equations above ( which my teacher told me to use ) and i keep getting the wrong answer. my wrong answer came out to be 4.6 somthing....

can anyone help me find my mistake and get the real answer for this?

Last edited: Jun 22, 2009
2. Jun 22, 2009

### LowlyPion

Clearly 4.6 s is not correct, if the period is .28 s.

So what angular value does ωt when it passes -1.44 ?

3. Jun 23, 2009

### weskerq8

thanks lowlypion for considering to help, actually i have solved this problem , what i was forgetting was to convert from degrees to radians. thats it :)

4. Jun 23, 2009

### LowlyPion

Unfortunately, that's a pretty easy thing to do on some calculators.

Good luck.