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Simple Harmonic Motion and time calculation

  1. Jun 22, 2009 #1
    1. The problem statement, all variables and given/known data

    An object is undergoing simple harmonic motion with period 0.280 s and amplitude 5.95 cm . At t=0 the object is instantaneously at rest at x= 5.95 cm.

    Calculate the time it takes the object to go from x= 5.95 to x= -1.44 .

    2. Relevant equations

    X=A.cos(wt) ------> the phase angle in this case is zero (we won't worry about it)
    w=2pi/T

    3. The attempt at a solution

    I have used the equations above ( which my teacher told me to use ) and i keep getting the wrong answer. my wrong answer came out to be 4.6 somthing....

    can anyone help me find my mistake and get the real answer for this?
     
    Last edited: Jun 22, 2009
  2. jcsd
  3. Jun 22, 2009 #2

    LowlyPion

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    Clearly 4.6 s is not correct, if the period is .28 s.

    So what angular value does ωt when it passes -1.44 ?
     
  4. Jun 23, 2009 #3
    thanks lowlypion for considering to help, actually i have solved this problem , what i was forgetting was to convert from degrees to radians. thats it :)
     
  5. Jun 23, 2009 #4

    LowlyPion

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    Unfortunately, that's a pretty easy thing to do on some calculators.

    Good luck.
     
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