Simple Harmonic Motion and time calculation

[weskerq8]

Homework Statement

An object is undergoing simple harmonic motion with period 0.280 s and amplitude 5.95 cm . At t=0 the object is instantaneously at rest at x= 5.95 cm.

Calculate the time it takes the object to go from x= 5.95 to x= -1.44 .

Homework Equations

X=A.cos(wt) ------> the phase angle in this case is zero (we won't worry about it)
w=2pi/T

The Attempt at a Solution

I have used the equations above ( which my teacher told me to use ) and i keep getting the wrong answer. my wrong answer came out to be 4.6 somthing...

can anyone help me find my mistake and get the real answer for this?

 

[LowlyPion]

Clearly 4.6 s is not correct, if the period is .28 s.

So what angular value does ωt when it passes -1.44 ?

 

[weskerq8]

thanks lowlypion for considering to help, actually i have solved this problem , what i was forgetting was to convert from degrees to radians. that's it :)

 

[LowlyPion]

thanks lowlypion for considering to help, actually i have solved this problem , what i was forgetting was to convert from degrees to radians. that's it :)

Unfortunately, that's a pretty easy thing to do on some calculators.

Good luck.