Simple Harmonic Motion: Determine Velocity at t=0.250s

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Homework Help Overview

The problem involves determining the velocity of a mass undergoing simple harmonic motion at a specific time, given its position function. The position is described by the equation x(t) = (2.00 cm)cos(5t - 4.00π), with parameters including mass and angular frequency.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between velocity and position in simple harmonic motion, with one attempting to apply the velocity equation directly. There is also a question regarding the basic relation connecting velocity and position.

Discussion Status

Some participants are exploring the application of the velocity equation and questioning the correctness of their substitutions. There is acknowledgment of potential errors in unit conversion affecting the results.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the information they can share or the methods they can use. There is an emphasis on understanding the underlying principles rather than simply providing answers.

Moe*
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_{}b]1. Homework Statement [/b)

The position of a 39.8 g oscillating mass is given by the equation x(t)= (2.00cm)cos(5t- 4.00\pi) where t is in seconds. Determine Velocity at t= 0.250s

M= 39.8 g
T= 1.2575 rad/s
K= 9.95e-1 N/m
initial postion= 2 cm

Homework Equations



V_{x}= -\omegaAsin(\omegat + \phi)

The Attempt at a Solution



the attempt i just substitued
V_{x}= -5 rad/s*2sin( 5.00(0.250)-4\pi)... but this didn't work and i don't understand why?
 
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for the the equations posted its supposed to be V subscript x= wAsin(wt + phi) and x(t) = (2.00cm)cos(5t - 4pi)
 
Moe* said:
The position of a 39.8 g oscillating mass is given by the equation x(t)= (2.00cm)cos(5t- 4.00\pi) where t is in seconds. Determine Velocity at t= 0.250s

What is the basic relation connecting velocity and position of any particle? Use that.
 
Moe* said:
_{}b]1. Homework Statement [/b)

The position of a 39.8 g oscillating mass is given by the equation x(t)= (2.00cm)cos(5t- 4.00\pi) where t is in seconds. Determine Velocity at t= 0.250s

M= 39.8 g
T= 1.2575 rad/s
K= 9.95e-1 N/m
initial postion= 2 cm

Homework Equations



V_{x}= -\omegaAsin(\omegat + \phi)

The Attempt at a Solution



the attempt i just substitued
V_{x}= -5 rad/s*2sin( 5.00(0.250)-4\pi)... but this didn't work and i don't understand why?
it seems work to me...
 
Your right it does work, i guess I entered in the wrong units when i answered the question( m/s instead of cm/s).
 

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