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**[SOLVED] Simple Harmonic Motion, Finding Time**

## Homework Statement

A 0.400 kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 10.0 cm.

Calculate the time interval required for the object to move from x = 0 to x = 4.00 cm.

## Homework Equations

The relevant equations for this should be:

x = Acos(ωt)

w = [tex]\sqrt{k/m}[/tex]

## The Attempt at a Solution

You should be able to solve the above equation for t...

cos(ωt) = x/A

ωt = arccos(x/A)

[tex]t = arccos(x/A)/\sqrt{k/m}[/tex]

Plugging in the following values:

x = 4 cm

A = 10 cm

k = 8 N/m

m = 0.400 kg

I get that t = .259s which is not right. Where am I going wrong?