Simple Harmonic Motion- From Uniform Circular Motion

Click For Summary

Homework Help Overview

The discussion revolves around the relationship between angular frequency and frequency in the context of simple harmonic motion and uniform circular motion. Participants are examining the equations provided by their instructor and textbook regarding angular frequency (W) and period (T), specifically focusing on the presence of the factor of 2π in the equations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the equations for angular frequency and period, questioning the role of the factor 2π. There is a discussion about the conversion between measuring frequency in Hertz and radians per second, as well as the implications of these conversions on the equations provided.

Discussion Status

Some participants are exploring the differences between the equations given by the instructor and the textbook, while others are considering the implications of measuring frequency in different units. There is an ongoing dialogue about the correctness of the equations and their interpretations, but no consensus has been reached yet.

Contextual Notes

Participants express confusion regarding the equations and their applications, indicating a need for clarification on the definitions and conversions between angular frequency and frequency in Hertz. The discussion reflects a mix of understanding and uncertainty about the material presented in class.

chantalprince
Messages
54
Reaction score
0

Homework Statement



I don't have a homework question exactly, but I need help with an equation please.


Angular frequency: W= 2 pi/T = 2(pi)(f) f= frequency

And- W = square root of (k/m) k = spring constant m= mass

So, wouldn't T = 2 pi / square root of (k/m) ??



My instructor has given us the following equations in class a few times. I cannot figure out what the heck is going on!

W = (2 pi) x the square root of(k/m)
T = (2 pi) x the square root of (m/k) -------> m/k this time

Any help is appreciated. I am so confused right now.





Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
This is simply because of the fact that:

\frac{1}{\frac{a}{b}}=\frac{b}{a}
 
Ok- but in the book it gives: W = sq. root of (k/m)

Instructor gives: W = 2pi x sq. root (k/m)

Whats with the 2 pi??

Thanks-
 
What's the difference between measuring angular frequency in Hz and measuring frequency in radians per second? That might give you an idea where the conversion comes from.
 
Ok...I'll sit down with that thought. So, either one works right? They are the same thing??
 
Ah I see what you're getting at now. There's a mistake in the equation for frequency:

\omega_{n} = \sqrt{\frac {k}{m}} (1)

where frequency is in radians per second.

But what if you want to express the frequency in Hertz? Well, we know that 1 Hz is equal to one cycle per second. In the case of circular motion, one cycle is equal to 2\pi radians.

So to convert from radians per second to Hertz, one must divide by 2\pi. Hence:

\omega = \frac {1}{2\pi} \sqrt{\frac{k}{m}} (2)

where frequency is now in Hertz.

Now let's express this in terms of the period of one cycle, T. Bear in mind that if you were simply to reciprocate the expression for frequency when expressed in radians per second (equation 1), you would be stating the length of time of rotation for one radian alone. Hence you have to multiply the expression by 2\pi now to obtain the period for a single cycle. This is now the same equation as you would obtain by reciprocating equation 2.

Hope this helps.
 

Similar threads

Replies
16
Views
2K
Replies
11
Views
3K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
7
Views
1K
  • · Replies 51 ·
2
Replies
51
Views
4K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
11
Views
2K