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## Homework Statement

A bolt of mass 2.10×10^-2 kg moves with SHM that has an amplitude of 0.245 m and a period of 1.495 s. The displacement of the bolt is + 0.245 m when t=0.

A.) Find the displacement of the bolt at time t=0.500s

## Homework Equations

## The Attempt at a Solution

**Part A.)**

[tex]ω= \frac{2π}{1.495}[/tex]

[tex]ω= 4.20[/tex]

Since the function starts at +0.245 I modeled the motion by this:

[tex]x(t) = Acos(ωt + \phi)[/tex]

[tex]x(t) = 0.245cos(4.20t)[/tex]

I then evaluated x(t) at t = .5 and I got that:

[tex]x(.5) = -.123[/tex]

Make sense?

(There are more parts to this problem, but I wanted to make sure I remember graphing of trig functions correctly.)