• Support PF! Buy your school textbooks, materials and every day products Here!

Simple harmonic motion of a machine part

  • Thread starter kaywond
  • Start date
2
0
1. Homework Statement
A machine part is undergoing SHM with a frequency of of 5hz and amplitude of 1.80cm. How long does it take the part to go from x = 0 to -1.80cm?


2. Homework Equations
x = Acoswt


3. The Attempt at a Solution
X is given and convert it to metres 0.018. I need to manipulate answer to get time.
angular velocity is 2pi x 5 = 31.41. It is just an equation manipulation. could someone please show me the technique?
 

Answers and Replies

The displacement is the negative of the amplitude.
 
CWatters
Science Advisor
Homework Helper
Gold Member
10,528
2,294
If the peak amplitude is 1.8cm then asking when the displacement is -1.8 makes it rather easy. No need to even use the sin button on the calculator :-)

Sketch displacement vs time. Mark the points 1.8m and -1.8m. If T is the period (=1/5) at what fraction of T does 1.8cm and -1.8cm occur?
 
2
0
thanks 1/5 equals 0.2. Then divide by 4 and 0.05 is the time in seconds
 
CWatters
Science Advisor
Homework Helper
Gold Member
10,528
2,294
0.05s is one valid answer but there are two possible valid right answers for this question. I recommend you give both.
 

Related Threads for: Simple harmonic motion of a machine part

Replies
3
Views
7K
Replies
5
Views
6K
Replies
4
Views
5K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
9
Views
5K
Replies
7
Views
2K
Replies
1
Views
2K
Top