# Simple harmonic motion of a machine part

1. Homework Statement
A machine part is undergoing SHM with a frequency of of 5hz and amplitude of 1.80cm. How long does it take the part to go from x = 0 to -1.80cm?

2. Homework Equations
x = Acoswt

3. The Attempt at a Solution
X is given and convert it to metres 0.018. I need to manipulate answer to get time.
angular velocity is 2pi x 5 = 31.41. It is just an equation manipulation. could someone please show me the technique?

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The displacement is the negative of the amplitude.

CWatters
Homework Helper
Gold Member
If the peak amplitude is 1.8cm then asking when the displacement is -1.8 makes it rather easy. No need to even use the sin button on the calculator :-)

Sketch displacement vs time. Mark the points 1.8m and -1.8m. If T is the period (=1/5) at what fraction of T does 1.8cm and -1.8cm occur?

thanks 1/5 equals 0.2. Then divide by 4 and 0.05 is the time in seconds

CWatters